The National Hockey League announced its finalists for the Vezina Trophy this morning.
The three finalists are all worthy candidates. The first being last year’s Vezina winner Henrik Lundqvist, goalie for the New York Rangers. The second is San Jose Sharks’ tender and Stanley Cup winner Antti Niemi. The final nominee is former Philadelphia Flyers and current Columbus Blue Jackets’ goalie Sergei Bobrovsky.
Bobrovsky was traded to Columbus last offseason for three draft picks and he easily stepped into the starting role for the Jackets. Bob took over for a revolving goalie carousel that included Steve Mason, Curtis Sanford and Allen York.
Bobrovsky, who played 83 total games for the Flyers, accumulated a record of 42-23-10. In his first year with the Flyers he had a .915 save percentage and a 2.59 GAA.
The 24 year old Russian tender had an amazing season with the Blue Jackets. Bob had a save percentage of .932 and a GAA of 2.00, all while posting a record of 21-11-6. During the season he had 4 shutouts, including the first of his NHL career on April 9, 2013 against San Jose.
Bobrovsky was named the NHL’s third star of the week once (Week ending March 17), First star of the week twice (Week ending March 10 and April 14) and third star of the month once (Month of March 2013).
The strong play between the pipes really helped Columbus down the stretch, nearly propelling the Jackets into the playoffs this season (for the second time ever).
We wish Bobrovsky the best in his Vezina nomination.
Should Bob win, he would be the first ever Russian-born goalie to do so. He would also be the only other goalie, other than Ed Belfour, to win the Vezina as an undrafted goalie since 1982.